![]() ![]() Pruébalo Sintaxis array. splice has already cleared the list after the first iteration of the loop, so it will not do any work for rest of the loop. El método splice () cambia el contenido de un array eliminando elementos existentes y/o agregando nuevos elementos. Your code is put inside a loop, and setup is called only before each loop. The splice () method is a built-in JavaScript array method that modifies the content of an array by removing, adding, or replacing elements. The splice method functions like a powerful Swiss Army Knife that gives you the ability to add new array elements and remove existing ones. Here's a small snippet: "(runs before each clocked test loop, outside of the timed code region)" ![]() I was thinking that Splice would have to allocate a whole new. Secondly, an initialized list has 50% removable elements so what difference does it make if you call push on a non-removable vs splice on a removable item? EDIT: Turns out my jsperf was horribly faulty - swapping still is faster in JS too. Firstly, even when arrays are (they are not, unless you are doing something really wild) represented as hash maps the splice algorithm would still have to re-map every numeric key, just like an array has to move every element.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |